(2x+y^2)(2y+4x-3y^2)=0

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Solution for (2x+y^2)(2y+4x-3y^2)=0 equation: 


Simplifying
(2x + y2)(2y + 4x + -3y2) = 0

Reorder the terms:
(2x + y2)(4x + 2y + -3y2) = 0

Multiply (2x + y2) * (4x + 2y + -3y2)
(2x * (4x + 2y + -3y2) + y2(4x + 2y + -3y2)) = 0
((4x * 2x + 2y * 2x + -3y2 * 2x) + y2(4x + 2y + -3y2)) = 0

Reorder the terms:
((4xy + -6xy2 + 8x2) + y2(4x + 2y + -3y2)) = 0
((4xy + -6xy2 + 8x2) + y2(4x + 2y + -3y2)) = 0
(4xy + -6xy2 + 8x2 + (4x * y2 + 2y * y2 + -3y2 * y2)) = 0
(4xy + -6xy2 + 8x2 + (4xy2 + 2y3 + -3y4)) = 0

Reorder the terms:
(4xy + -6xy2 + 4xy2 + 8x2 + 2y3 + -3y4) = 0

Combine like terms: -6xy2 + 4xy2 = -2xy2
(4xy + -2xy2 + 8x2 + 2y3 + -3y4) = 0

Solving
4xy + -2xy2 + 8x2 + 2y3 + -3y4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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